题目
给两个整数数组 A 和 B ,返回两个数组中公共的、长度最长的子数组的长度。
思路
设数组A长度为n,B长度为m动态规划:
设置动态规划数组dp[n+1][m+1],dp[n][m]=0。
从A[n-1]和B[m-1]开始向前遍历比较,可以得出伪代码:
if A[i]==B[j]:dp[i][j]=dp[i+1][j+1]+1;
else if …
<sql id="text">a,b,c</sql><select>select <include/>from A a</select>
<select>select <include refid="text" prefix="a." />from A a join B b on a.id = b.id</select>prefix=“a.”
Maven setting 文件配置<?xml version="1.0" encoding="UTF-8"?><!--
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